1/3x+1/x^2=x-4/x^2

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Solution for 1/3x+1/x^2=x-4/x^2 equation: 


D( x )

x^2 = 0

x^2 = 0

x^2 = 0

1*x^2 = 0 // : 1

x^2 = 0

x = 0

x in (-oo:0) U (0:+oo)

(1/3)*x+1/(x^2) = x-(4/(x^2)) // - x-(4/(x^2))

(1/3)*x-x+1/(x^2)+4/(x^2) = 0

5*x^-2-2/3*x = 0

x*(5*x^-3-2/3) = 0

5*x^-3 = 2/3 // : 5

x^-3 = 2/15

-3 < 0

1/(x^3) = 2/15 // * x^3

1 = 2/15*x^3 // : 2/15

15/2 = x^3

x^3 = 15/2 // ^ 1/3

x = (15/2)^(1/3)

x = 0

x = 0

x in { 0} 

x = (15/2)^(1/3)

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